⇒ You will be familiar with the equation that we use to calculate the increase in gravitational potential energy when a mass is lifted in a gravitational field
⇒ We calculate the change of gravitational potential energy using the equation: ΔEp = mgΔh
⇒ This shows the gravitational field lines (in green) close to the surface of a planet, where the gravitational field strength is 5Nkg-1
⇒ When a 1kg mass if lifted through a height of 20m in this field, the equation above tells us that the increase in gravitational potential energy of the mass is 100J
⇒ These calculations lead us to the idea of gravitational potential difference, which can be defined as the change in gravitational potential energy per kilogram
⇒ Gravitational potential is given the symbol V, and gravitational potential difference is given the symbol ΔV. Since ΔEp = mgΔh, it follows that:
⇒ Gravitational potential has units of Jkg-1
⇒ The above image also shows equipotentials close to the surface of the planet
⇒ In the diagram these look like lines, but in three dimensions they are surfaces
⇒ Equipotential surfaces are always at right angles to the gravitational field
⇒ To be exact, in the link between gravitational field and potential, we should link them with this equation:
⇒ The significance of the minus sign is that the potential gradient ΔV / Δh is in a positive direction upwards, because the potential increases as the height about the planet increases
⇒ Look at the following graph: this shows how the gravitational force acting on an object (with a certain mass, m) changes as it approaches a planet (with a distinct mass, M):
⇒ This graph shows that at a certain distance from the planet (r) a force is acting on the object
⇒ If this object were to move a small distance away form the planet (Δr) we are able to calculate how much the gravitational potential energy increases:
⇒ Calculating the increase in gravitational potential energy when the mass is moved much greater distances (e.g. r1 to r2) is a little trickier because the force moves as the distance moves
⇒ In this scenario, we can calculate the gravitational potential energy as follows:
⇒ Using this equation, we can derive a formula for the increase in gravitational potential (ΔV), because:
⇒ This equation allows us to think about defining gravitational potential close to a planet
⇒ When r2 is equal to infinity, 1/r2 is essentially 0, so the gravitational potential change in moving from r1 to inifinity is:
⇒ However, we choose to define infinity as the point of 0 gravitational potential for all stars and planets
⇒ Therefore, as we defined the gravitational potential as 0 at inifinity, it means the gravitational potential near to any planet is a negative quantity, because gravitational potential energy will decrease as an object falls towards a planet
⇒ This leads to the following definition of gravitational potential (V) of an object positioned at a distance (r) from the centre of some massive object:
⇒ The following image shows the gravitational field lines and equipotentials near a planet:
⇒ The equipotentials are shown in equal steps of 1 x 107 JKg-1 from the surface of the celestial body (at G), where the potential is -8 x 107 JKg-1, to A, where the potential is -2 x 107 JKg-1
⇒ The diagram shows two important linked points:
⇒ These two statements are linked by a formula shown earlier:
⇒ These equations are exactly the same, except that Δh has been used for a change in height, and Δr has been used for a change in distance from the centre of the planet
⇒ Also see our notes on: